0=7h^2+16h-3596

Solution for 0=7h^2+16h-3596 equation:

0=7h^2+16h-3596

We move all terms to the left:

0-(7h^2+16h-3596)=0

We add all the numbers together, and all the variables

-(7h^2+16h-3596)=0

We get rid of parentheses

-7h^2-16h+3596=0

a = -7; b = -16; c = +3596;
Δ = b2-4ac
Δ = -162-4·(-7)·3596
Δ = 100944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100944}=\sqrt{144*701}=\sqrt{144}*\sqrt{701}=12\sqrt{701}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-12\sqrt{701}}{2*-7}=\frac{16-12\sqrt{701}}{-14}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+12\sqrt{701}}{2*-7}=\frac{16+12\sqrt{701}}{-14}
$